Refactor transaction logging to simple SLF4J use

This commit is contained in:
Robin Bygrave
2013-04-15 23:16:08 +12:00
parent b5ef07bab9
commit cbd7b5e912
60 changed files with 2976 additions and 4529 deletions
@@ -66,7 +66,7 @@ public class TestSubQuery extends TestCase {
String sql = pq.getGeneratedSql();
String golden = "(t0.one_key) in (select t0.one_key from ckey_parent t0) ";
String golden = "(t0.one_key) in (select t0.one_key from ckey_parent t0) ";
if (sql.indexOf(golden) < 0)
{
@@ -131,7 +131,7 @@ public class TestSubQuery extends TestCase {
// TODO: If, after bugfixing, the system still join against vehicle I do not know now, in our case, it is not necessary if not
// using it in the where clause
String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0 left outer join vehicle t1 on t1.id = t0.vehicle_id )";
String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0 left outer join vehicle t1 on t1.id = t0.vehicle_id )";
if (sql.indexOf(golden) < 0)
{
System.out.println("failed sql:"+sql);
@@ -164,7 +164,7 @@ public class TestSubQuery extends TestCase {
String sql = pq.getGeneratedSql();
System.err.println(sql);
String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0 left outer join vehicle t1 on t1.id = t0.vehicle_id where t1.license_number = ? )";
String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0 left outer join vehicle t1 on t1.id = t0.vehicle_id where t1.license_number = ? )";
if (sql.indexOf(golden) < 0)
{
System.out.println("failed sql:"+sql);
@@ -195,7 +195,7 @@ public class TestSubQuery extends TestCase {
String sql = pq.getGeneratedSql();
System.err.println(sql);
String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0 left outer join vehicle t1 on t1.id = t0.vehicle_id )";
String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0 left outer join vehicle t1 on t1.id = t0.vehicle_id )";
// OR without join
// String golden = "(t0.id) in (select t0.vehicle_id from vehicle_driver t0)";
if (sql.indexOf(golden) < 0)